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Survival mode


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2008 Oct 9, 9:33am   25,672 views  286 comments

by Peter P   ➕follow (2)   💰tip   ignore  

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What should we do now?

Let's calm down for a while and come up with a checklist.

* How should we secure our food source?
* How should we protect our physical safety?
* How do we thrive?

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278   thenuttyneutron   2008 Oct 12, 6:36pm  

Power = (I^2)*R (resistance heating)
dV = I*R

I=current
R=Resistance

If you can raise the voltage, you can reduce the line losses. This is why high lines are stepped up to the thosands of volts that they run at. The reason for this is the decreased ampes on the line. The power is carried away on the wave action of the electron going back and forth.

279   thenuttyneutron   2008 Oct 12, 6:44pm  

http://www.theoildrum.com/node/4636

We have the solution to this problem.

280   Duke   2008 Oct 12, 10:26pm  

Looks like my man Krugman has won the nobe prize for economics.
Always a good read when he is not wonking politics.

281   Duke   2008 Oct 12, 11:05pm  

Can we start a new thread?
Just so I don't have to wade through this garbage?

282   justme   2008 Oct 12, 11:22pm  

Guys, I have not been reading this thread yesterday, but take it from an EE with quite a few years of additional education on top of the basic degree (if you catch my drift):

There has been a few misleading and/or errant statements made about certain electrical topics in this thread yesterday. I'm not quite in the mood to dissect all of it, but let me just clarify one or two points.

First, I should caution that there are many different ways of saying the same thing here, but let me just try to say it one way and see if that makes sense to everyone.

The reason that high voltage in a transmission system does not translate into hot and melting wires is that the VOLTAGE DROP along the wire is quite small. Note that there is a difference between the voltage drop along the wire and the voltage drop across the load that is connected between the two (or more) wires. The voltage drop across the load does (mostly) productive work. The voltage drop along the wire is plain loss.

More detail:

The reason that high voltage transmission is more efficient is that lower current is required to transmit tghe same power (P=V*I, V goes up, I goes down, for constant P). The loss in the wire is P(loss)=I^2*R, with a lower I than before.

Of course, there is more to the story than this, because there also are losses in the insulating medium (or "dielectric") between the wires (air, rubber, oil in transformers, etc etc). At some point, diminishing returns are going to set in when you increase the voltage, because the insulation gets prohibitive, the wires have to be spaced too far apart, etc etc etc.

Now, as I had mentioned a few months ago, one of the reason that DC transmission systems can be more efficient than AC , is that dielectric losses tend to be lower when there is a constant electric field rather than an alternating electric field. The latter is jerking the bound electrons in the insulator around quite a bit, and energy is lost. This is all a bit folksy a way of saying it, but you get the idea.

I agree with Fuzzy about current density. It is just an alternative way of saying the same thing as I just did. And I will defer to Neutron on most things nuclear :-).

283   justme   2008 Oct 12, 11:25pm  

Oh, I did not see Neutron's 1:35 am post. Also correct.

284   justme   2008 Oct 12, 11:30pm  

Duke,

I can agree that discussion of energy and energy conversion systems is a bit OT, but it sure has a profound effect on the economy in general and housing matters as well.

I think those exchanges are very worthwhile.

285   justme   2008 Oct 12, 11:35pm  

Duke,

Yeah, congratulations to Krugman, one of many decent economists that have advocated buying preferred equity rather than buying bad assets.

286   SP   2008 Oct 12, 11:45pm  

Duke Says:
Can we start a new thread?

It's up.

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